landrew's Comments

@ Ryan S

I think you mean Prototype, not Stereotype. One can have a prototype in mind of a chair, but a bean-bag chair, a laz-y-boy or a lawn chair are exemplars of the Chair prototype.

You can find similar discussions on prototype models as applied to birds.
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That's the problem Josh. How you see it is at issue. You're picking B because you know what A, C and D are. That means you are not "choos(ing) an answer to this question at random."
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Hey Samuel,
What you said seems to make sense. I think you bring up an important point about randomness or single-blind selection.
I'm having second thoughts on my previous answer. When considering "Schrodinger's Cat" (and maybe "The Monty Hall Effect" applies here too), I think maybe A or D is correct.
Let me throw this at you...so, if I didn't know what the values for A, B, C and D were and randomly picked A (to exclusion and without knowledge of B, C and D's values) then A would be correct since my 1-4 chance of randomly selecting a the correct answer of 25% is right. Likewise, if my first and only pick was D (to exclusion and without knowledge of A, B and C's values) then I would be right for the same reason. To the extreme, pretend A, B, C and D all had a value of 25%, but of course I don't this because it is a random selection then regardless of which letter I picked I would be right. I have a 1 in 4 choice to make the right selection (let's continue to pretend they are all 25% and I chose C). As long as I don't know what the answers are then until those other answers are revealed to me they could be every possible answer from 0% - 100%,"none of the above," "False," "Blue," a random word from the dictionary or even BLANK.
So, if I randomly chose C and it is 25% then what are the chances that A, B or D would also be 25% when they could hold ANY value? Almost 0%. Better chances winning the lottery.

The problem with this question is that we know what we shouldn't. One cannot randomly select an answer when they know in advance what the answers are.

I can see B being correct if I knew the values for A, C and D beforehand. But if I know that there are two 25% answers, then that knowledge would remove the random element that the question requires which you noted.

Have I made it more confusing? hahaha
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No way would it B, 50%

You have a 1 in 4 chance, 25%, of selecting B.
Likewise, you couldn't pick A or D since you have a 2 in 4 chance, 50%, of selecting the same answer.
And C is a non-issue.
Therefore, options A, B, C and D are all incorrect.

I think the only way to answer the question correctly is to answer it directly.
"If I chose A, B, C or D as an answer to this question at random, the chance that I would be correct is 0%"

But I do like the idea of changing C to 0% too!
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Profile for landrew

  • Member Since 2012/08/06


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